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$.inArray()/$.isArray()/$.merge() 본문

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$.inArray()/$.isArray()/$.merge()

Remi 2021. 7. 25. 14:05
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<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=\, initial-scale=1.0">
    <title>Document</title>
    <script src="jquery.js"></script>
    <script>
        $(function(){
            var arr1 = ["서울","대전","부산","전주"];
            var arr2 = ["한국","미국","일본","중국"];
            var obj = {
                "name" : "정부장",
                "area" :"서울"
            }

            var idxNum = $.inArray("부산",arr1);
            console.log(idxNum);

            var okArray1 = $.isArray(arr1);
            var okArray2 = $.isArray(obj);
            console.log(okArray1);
            console.log(okArray2);

            $.merge(arr2,arr1);
            console.log(arr2);

        });
    </script>
</head>
<body>
    
</body>
</html>

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